c^2+4c=21

Solution for c^2+4c=21 equation:

Simplifying
c2 + 4c = 21

Reorder the terms:
4c + c2 = 21

Solving
4c + c2 = 21

Solving for variable 'c'.

Reorder the terms:
-21 + 4c + c2 = 21 + -21

Combine like terms: 21 + -21 = 0
-21 + 4c + c2 = 0

Factor a trinomial.
(-7 + -1c)(3 + -1c) = 0

Subproblem 1
Set the factor '(-7 + -1c)' equal to zero and attempt to solve:

Simplifying
-7 + -1c = 0

Solving
-7 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -1c = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -1c = 0 + 7
-1c = 0 + 7

Combine like terms: 0 + 7 = 7
-1c = 7

Divide each side by '-1'.
c = -7

Simplifying
c = -7
Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Solution
c = {-7, 3}